25x ^ 2-10x + 1-36y ^ 2

d) 16x 2 + 8x + 1 e) 9x 2 – 16y 2 f) 4x 3 – 4x g) (x + 1) 2 – (x – 1) 2 h) 9x 2 + 6x + 1 – 25y 2 i) 25x 2 – 10x + 1 – 36y 2 j) x 3 + x – 3x 2 – 3 k) x 2 + y – xy – x

25x 2 – 10x + 1 – 36y 2. Solution Aug 06, 2018 · Factorize each of the following algebraic expressions: 25x^2 – 10x + 1 – 36y^2. asked Mar 8, 2020 in Factorization by Renuka01 (67.2k points) factorisation of 8. 25x 2-10x-1-36y 2. 9. X2+2xy+y 2-a2+2ab-b 2 10. 5x 2-16x- 21 Q-5 Find the value of:- X3 -8y3 -36xy-216, when x=2y+6 R S Aggarwal and V Aggarwal Solutions for Class 9 Mathematics CBSE, 3 Factorisation of Polynomials.

08.03.2021

C) 3. D) −6. E)2. 3. 6. Solve. 1 x − 1.

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a 2 + 2ab + b 2-c 2 Solution: Question 25. 49 -x 2 – y 2 + 2xy Solution: Question 26.

Factorise-25x^2-10x-36y^2+1 - 7020521 1. Log in. Join now. 1. Log in. Join now. Ask your question. ishikaawana6049 09.12.2018 Math Secondary School +5 pts. Answered Factorise-25x^2-10x-36y^2+1 2 See answers Answers

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16y^2-25x^2+10x-1. See steps. Step by Step Solution. Step 1 : Equation at the end of step 1 : (((16 • (y 2)) - 5 2 x 2) + 10x) - 1 Step 2 : Equation at the end of step 2 : ((2 4 y 2 - 5 2 x 2) + 10x) - 1 Step 3 Apply the distributive property by multiplying each term of 25x^{2}+10x+1 by each term of 2x-3.

Cancel the common factors. Tap for more steps 27/07/2020 Factorise:25x^2-10x+1-36-y^2 2 See answers Brainly User Brainly User Here is ur answer abhi569 abhi569 25x² -10x +1 -36-y² (5x)² -2(5x) +1² -(6)² -y² (5x-1)² -(6-y) (6+y) I hope this will help you -by ABHAY New questions in Math. 2) Vidit travels 30 km 50 m everyday. Out of this he travels 10 km 300 m by rickshaw and the rest by bus. How much distance does he travel by bus? good 19/05/2013 25x 2 - 10x = 5x • (5x - 2) Equation at the end of step 3 : 5x • (5x - 2) = 0 Step 4 : Theory - Roots of a product : 4.1 A product of several terms equals zero. When a product of two or more terms equals zero, then at least one of the terms must be zero.

= [(5x – 1) – 6y] [(5x – 1) + 6y]. = (5x – 1 – 6y)( 5x – 1 + 6y). It may be helpful to look at one of the examples at the end of the last section where we solved an equation of the form a{x}^{2}+bx+c=0 The solutions to a quadratic equation of the form a{x}^{2}+bx+c=0 Solve the equation {x}^{2}+1 Algebra II. Factor out the GCF 18x 3 + 24x 2 + 36x. (5n2 + 3) (3n + 1). 3 (5n2 - 3) 2 (x - 6y) (x2 + 6xy + 36y2).

b)25x^2 - 10x + 1 -36y^2. c)5 * ((Root)) 5 x^2 +30x + 8* ((Root)) 5. d)27-125a^3-135a+225a^2.

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equation 16x2 + 25y2 = 400, and sketch the ellipse. To be able to read any information from this equation, I'll need to rearrange it to get "=1", so I'll divide through by 400. This gives 25(x2 + 4x + 4) + 4(y2 – 10y

1 Answer +1 vote . answered Mar 8, 2020 by VinayYadav (67.1k points) selected Apr 3, 2020 by Renuka01 . Best answer Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor. x 4 + 10x 3 + 25x 2 = x 2 • (x 2 + 10x + 25) Trying to factor by splitting the middle term 4.2 Factoring x 2 + 10x + 25 The first term is, x 2 its coefficient is 1 .